Ajax Form

$(function() {
    $('#form').submit(function(e) {
        e.preventDefault();
        data = new FormData($('#form')[0]);
        console.log('Submitting');
        $.ajax({
            type: 'POST',
            url: 'post.php',
            data: data,
            cache: false,
            contentType: false,
            processData: false
        }).done(function(data) {
            console.log(data);
        }).fail(function(jqXHR,status, errorThrown) {
            console.log(errorThrown);
            console.log(jqXHR.responseText);
            console.log(jqXHR.status);
        });
    });
});